If thermal cofficient of linear expansion of metal is 1.5 × 10–5 °C–1 then its thermal coefficient of volume expansion is
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Answer:
thermal coefficient of volume expension is 45×10^-6/°C
Explanation:
We know that the volume of a body is given as:
[V]=L ^3
Therefore, the relation between the coefficient of linear expansion and volume expansion is written as:
coefficient of volume expansion= 3 * coefficient
of linear expansion
• γ=3α
γ=3×15×10 ^−6
coefficient of volume expansion γ=45×10 ^−6 /°C
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