if theta =30 verify that sin (60+theta )-sin(60-theta )=sin theta
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Step-by-step explanation:
given:
theta =30
to prove:
sin (60+theta )-sin(60-theta )=sin theta
solution:
taking LHS
sin (60+theta)-sin(60-theta)
on putting theta =30 , we get
=sin (60+30)-sin(60-30)
=sin90°-sin30°
=1-(1/2) [sin90°=1, sin30° =1/2]
=1/2=sin30°=sin theta=RHS
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