Question

If theta= 30 verify that:tan 2 theta = 2 tan theta/1- tan square
theta

Answer 1

Here is the solution for the question you asked me

Answer 2

Answer:

Step-by-step explanation:

The given equation is :

$tan{\theta}=\frac{2tan{\theta}}{1-tan^{2}{\theta}}$

Now, if ${\theta}=30^{{\circ}}$, then the equation becomes,

$tan2(30)^{{\circ}}=\frac{2tan30^{{\circ}}}{1-tan^{2}30^{{\circ}}}$

$tan60^{{\circ}}=\frac{2{\times}\frac{1}{\sqrt{3}}}{1-\frac{1}{3}}$

$\sqrt{3}=\frac{\frac{2}{\sqrt{3}}}{\frac{2}{3}}$

$\sqrt{3}=\sqrt{3}$

Hence proved.