if theta =45 degree.verify that cos 2 theta =cos square theta -sin square theta
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Step-by-step explanation:
A = 45°
L.H.S
cos2A = cos2 (45°)
= cos90° = 0
R.H.S
cos^2A - sin^2A
= cos^2 45° - sin^2 45°
= (1/√2)^2 - (1/√2)^2
= 1/2 - 1/2 = 0
L.H.S = R.H.S , hence proved
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