Question

If theta=60 show that sin theta=tan theta/root 1+tan square theta

Answer 1

Answer:

given,

theta = 60°

LHS=Sin theta

=Sin 60°

RHS =

$\frac{tan \: theta}{ \sqrt{1 + tan ^{2} theta} }$

$\frac{tan \: theta}{ \sqrt{sec^{2} } theta}$

$\frac{tan \: theta}{sec \: theta}$

$\frac{ \frac{sin \: theta}{cos \: theta} }{ \frac{1}{cos \: theta} }$

$\frac{sin \: theta}{cos \: theta} \times cos \: theta$

$sin \: theta$

sin 60°

therefore,

LHS=RHS

hence proved