if theta in an acute angle and sin theta = cos theta ,find the value of 2 tan square theta + sin square theta -1
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4
maybe correct I am not sure
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bharat4911:
its correct
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2
sin©=cos©
hence ©=45°
2tan²© + sin²©-1
2tan²45° + sin²45° -1
2× 1² + (1/√2)² -1
2 + 1/2 -1
2 + 1 -2/1
2-1
1
hence ©=45°
2tan²© + sin²©-1
2tan²45° + sin²45° -1
2× 1² + (1/√2)² -1
2 + 1/2 -1
2 + 1 -2/1
2-1
1
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