Question

if theta is 60 then 1+tan^2 upon 2+tan​

Answer 1

Answer:

$4(2-\sqrt{3})$

Step-by-step explanation:

A= ∅= 60  =>  tanA =√3

$\frac{1+tan^{2}A}{2+tanA} =\frac{1+3}{2+\sqrt{3}}$

             $=\frac{4(2-\sqrt{3})}{4-3}$

             $=4(2-\sqrt{3})$