iF THETA IS A POSITIVE ACUTE ANGLE AND TAN 3 THETA = COT(60- THETA), THEN FIND THE VALUE OF SIN 3 THETA, PLS HELP I NEED IT RIGHT NOW I WILL MARK BRRAINLIEST
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SOLUTION
GIVEN
θ is positive acute angle and
tan 3θ = cot ( 60° - θ )
TO DETERMINE
The value of θ
EVALUATION
Here it is given that θ is positive acute angle and tan 3θ = cot ( 60° - θ )
Now
tan 3θ = cot ( 60° - θ )
⇒ cot ( 90° - 3θ ) = cot ( 60° - θ )
⇒ ( 90° - 3θ ) = ( 60° - θ )
⇒ - 3θ + θ = 60° - 90°
⇒ - 2θ = - 30°
⇒ θ = 15°
FINAL ANSWER
θ = 15°
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