if theta is an acte angle and 4 sin theta = 3
then the value of 4 sin²theta -3 cos² theta +2 is
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Answer:
sin thetha = 3/ 4 then,
cos theta = √7/4
4 sin² theta - 3 cos² theta + 2
4 * 9/16 - 3 * 7/16 +2
47/16
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4sin theta= 3
sin theta =3/4 which is equal to perpendicular upon hypotenuse
for cos we can find the base
by Pythagoras theorem
H^2= P^2+B^2
4²= 3²+b²
4²-3²=b² = 16-9= √7
base = √7
cos theta = base / hypotenuse. = √7/4
now put the values in equation
4 sin²theta-3cos² theta+2
4(3/4)²-3(√7/4)²+2
4×9/16-3×7/16+2 = 9/4 -21/16+2
and the LCM is 16 =36-21+32/16
the answer is 47/16
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