if theta is an acute angle and sin theta = cos theta, find : 3 tan^2
+ 2 sin^2 theta+cos^2 thata-1.
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Answer:
then....
3 sin²/sin² + 2sin² theta + sin² theta -1
= 3+3sin² theta -1
=3sin² theta +2
Now, since sin theta = cos theta....
theta = 45°
3sin²(45)+2
=3(1/√2)²+2
=3/2+2
=7/2
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