Question

If theta is an acute angle and sin theta = cos theta, find the value of : 2 tan^2 theta + sin^2 theta - 1.

Answer 1

sin theta = cos theta
so...theta= 45°

now....
$2tan {}^{2} \alpha + sin {}^{2} \alpha - 1 \\ = 2tan {}^{2} 45 + sin {}^{2}45 - 1 \\ = 2(1) {}^{2} +( \frac{1}{ \sqrt{2} } ) { }^{2} - 1 \\ = 2 + \frac{1}{2} - 1 \\ = \frac{4 + 1 - 2}{2} \\ = \frac{3}{2}$
hope this helps.....
if correct...
Mark as brainlist Please....

Answer 2

Hope it helps.......

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