if theta is an acute angle and sin theta + cosec theta=2, find sin¹³ theta+ cosec¹³ theta
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Answer:
sinθ=cosθ
cosθ
sinθ
=
cosθ
cosθ
tanθ=1=tan45
o
θ=45
o
Therefore, 2tan
θ
+sin
2
θ−1=2tan
4
5
o
+sin
2
45
o
−1
=2×(1)
2
+(
2
1
)
2
−1=2+
2
1
−1=
2
3
.
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