If theta is an acute angle and sintheta=costheta, find the value of : 3tan^2theta + 2sin^2theta - 1
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If theta is an acute angle and sin theta = cos theta , then value of 2 tan^2 theta + sin^2 theta - 1 !! Plz fast Only 1 day to go for my Maths SA1 :(((
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θ is an acute angle
and sin θ = cos θ
⇒ sin θ = sin (90° - θ)
⇒ θ = 90° - θ
⇒ θ + θ = 2θ = 90°
⇒ θ = 45°
Thus,
2tan2θ + sin2θ - 1 = 2tan245° + sin245° - 1 = 2(tan 45°)2 + (sin 45°)2 - 1
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