Question

If theta is an acute angle such that cos theta =3/5 ,then sin theta tan theta -1 by 2tansquare theta

Answer 1

Please mark this answer as brainliest.......

Answer 2

Pythagoras of Samos was an ancient Ionian Greek philosopher and the eponymous founder of Pythagoreanism.

Given: $cos\theta=\frac{3}{5}$

Find: $\frac{sin\theta tan\theta-1}{2tan^2\theta}$

First, we find $AB.$

$(AC)^2+(BC)^2+(AB)^2\\25=9+AB^2\\AB^2=16\\AB=4$

$Sin\theta=\frac{4}{5},tan\theta=\frac{4}{3}$

$\frac{\frac{4}{5}\times \frac{4}{3}-1 }{2\times (\frac{4}{3})^2 }=\frac{\frac{16}{15}-1 }{\frac{32}{3} } =\frac{\frac{16-15}{15} }{\frac{32}{3} }$

$\frac{\frac{1}{15} }{\frac{32}{3} }=\frac{1\times 3}{5\times 32}=\frac{3}{160}$