IF theta is positive acute angle and tan^2 theta + cot ^2 theta = 82/9 , find the value of tan theta + cot theta
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tan^2 theta + cot ^2 theta = 82/9
Adding 2 both side we get
tan^2 theta + cot ^2 theta + 2 = 82/9 +2 =100/9
(tan theta + cot theta)^2 =100/9
tan theta + cot theta = 10/3
Adding 2 both side we get
tan^2 theta + cot ^2 theta + 2 = 82/9 +2 =100/9
(tan theta + cot theta)^2 =100/9
tan theta + cot theta = 10/3
debanti:
IT WILL BE 10/ 3 , I THINK ....
sorry sorry... by mistake. I hope you got answer to it...
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tan teeta + cot teeta = 10/3
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