Question

if theta1 and theta2 are the solutions of the equation acos2teta+bsin2teta=c, tanteta1 is not equal to tanteta2 and a+c is not equal to 0 then find 1)tanteta1+tanteta2 and 2) tanteta1 x tanteta2​

Answer 1

Answer:

sin(θ+α)=ksin2θ

sinθcosα+cosθsinα=2ksinθcosθ

Change the equation in tan

2

θ

form and let tan

2

θ

=t, then obtained equation is sinαt

4

−(2cosα+4k)t

3

+t(4k−2cosα)−sinα=0

S

1

=

sinα

2cosα+4k

,S

2

=0

S

3

=

sinα

4k−2cosα

,S

4

=−1