if they are added in parallel sequence of five pieces similar to the resistivity of the five Omega then their equal resistance will be
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1/R=1/r1 + 1/r2 + ......+ 1/rn
r1=r2=r3=r4=r5=5 ohm
therefore
1/R = 1/5+1/5+1/5+1/5+1/5
= 5/5=1 ohm
therefore the equivalent resistance is 1 ohm when 5 resistors of 5 ohm each are connected in parallel
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