If they give us triangle ABC;B=90° find the ratio of sinC ,sinA,cosC ,CosA ,Tan A
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I hope this will help you
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Step-by-step explanation:
The given triangle is ABC.
And B = 90°.
Let AB = Perpendicular
BC = Base
AC = Hypotenuse.
FORMULA :-
1) SinA = P/H
2) CosA = B/H
3) TanA = P/B
4) CotA = B/P
5) CosecA = H/P
6) SecA = H/B
So,
SinC =AB/AC
SinA = BC/AC
CosC = BC/AC
CosA = AB/AC
TanA = BC/AB
THANKS.
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