if third term of an AP is 11 and fifth term is 19 . find AP
Answers
Step-by-step explanation:
If third term of an AP is 11 then we have, =a+2d=11----(1)
and If the fifth term of AP is 19 then we have,
=a+4d=19-----(2)
On solving (1) and (2) equation we get, d=4 and a=3
Hence, AP is 3, 7, 11, 15, 19.....
Step-by-step explanation:
The third term of AP (a3) = 11
And, Fifth term (a5) = 19
we know that,
a3 = a+ 2d
11 = a + 2d ------------ equation 1
then,
a5 = a + 4d
19 = a + 4d ------------equation 2
By using elimination method in equation 1 and 2 ,
a+4d = 19
a+2d = 11
-------------- (subtract)
2d = 8
d = 4 ------------------ equation 3
putting value of d in equation 1 we get,
a= 3 (first term. of AP)
second term (a2) = a+d
3+4= 7
fourth term (a4) = a+3d
15
Hence , AP is 3, 7, 11, 15, 19
with common difference 4