if third term of ap is 18 and seventh term of 30 find the series
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Step-by-step explanation:
Let the first term of an AP be a and common difference be d
The third term of an AP is a+2d, given that it is equal to 18
⇒a+2d=18
The seventh term of an AP is a+6d, given that it is equal to 30
⇒a+6d=30
By subtracting first equation from second equation , we get 4d=12
⇒d=3
By substituting the value of d it in first equation, we get a=12
Therefore sum of first 17 terms in AP is
2
_ (2×12 + (30-1) × 3)
30
2
_ ×111
30
=7.4
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