if third term of ap is 18 and seventh term of 30 find the series
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a3 = 18. , a+2d=18
a7=30 , a+6d=30
by subtracting eq1 and 2
a+2d=18
a+6d=30
we get-4d = -12.
d = 3
a+2d = 18
a+2×3=18
a+6=18
a =12
a = 12
a2 = a+d =12+3=15
a3 = a+2d =12+2×3=18
a4 = a+3d =12+3×3=21
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