Question

If this wall clock falls and breaks into two pieces... the addition of digits in the smaller piece is 31 and the digits in the bigger piece add up to 30. how did the wall clock break

Answer 1

Question says that sum of digits in the smaller piece is 31 and in larger piece is 30

so total sum = 30+31=61

Notice that "digit" means "0,1,2,3,4,5,6,7,8,9"

So if you add only digits then sum=61 is not possible in any case

like

[1+2+3+4+5+6+7+8+9+10+11+12]

break numbers into digits

[1+2+3+4+5+6+7+8+9+1+0+1+1+1+2]

=51

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Answer is possible only if we consider to add numbers not the digits.

If we break the clock so that number 12 seprates in 1 and 2. and number 8 gets damaged fully then we get:

Sum of numbers in small piece = 1+11+10+9=31

Sum of numbers in bigger piece = 7+6+5+4+3+2+1+2=30

So the final answer is that clock has to break number 12 so that 1 and 2 gets separated and number 8 gets damaged completely.

Answer 2

We have sum of digits in the smaller piece is 31 and in larger piece is 30

The total sum = 30+31=61

Notice that ""digit"" means ""0,1,2,3,4,5,6,7,8,9""

So if you add only digits then sum=61 is not possible in any situation.

[1+2+3+4+5+6+7+8+9+10+11+12]

Then, break numbers into digits

[1+2+3+4+5+6+7+8+9+1+0+1+1+1+2] =51

Question is doable only if we consider adding numbers not the digits.

If we break the clock so that number 12 separates in 1 and 2. And number 8 gets damaged fully then we get:

Sum of numbers in bigger piece = 7+6+5+4+3+2+1+2=30

Sum of numbers in small piece = 1+11+10+9=31

So the final result is that clock has to break number 12, therefore, that 1 and 2 gets separated and number 8 gets broken completely.