if thita and bita are the roots of the quadratic equation x2-2x-7=0, find the value thita square+ bita square
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Step-by-step explanation:
theta sq. + beta sq. =(theta+beta)^2-2theta * beta
theta*beta =c/a=-7/2
theta +beta=-b/a=2/2=1
putting values
1^2-2*(-7/2)=8
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It's a bit messy...!! But I hope it'll help ya...
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