If Thita is acute and 3 sinThita = 4cosThita. Find the value of 4sin^2Thita - 3cos^2Thita +2.
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Solution:-
4sin 2 θ=1
⇒sin 2 θ= 41
⇒sinθ= 21 or − 21
So, the values of θ are
6π,65π, 6 7π and 6 11π
So, θ takes 4 values.
Hence proved!!
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