If thr ratio of the sum of first n terms of two A.P's is (7n + 1) : (4n + 27), find the ratio of the mth terms..
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HELLO DEAR
GIVEN RATIO OF SUM OF N TERMS OF TWO AP’s
= (7n+1):(4n+27)--------------(1)
Let’s consider the ratio these two AP’s mth
terms as am : a’m →(2)the nth term of AP
formula, an = a + (n – 1)d
equation (2) ,
am : a’m = a + (m – 1)d : a’ + (m – 1)d’
On multiplying by 2,
we get
am : a’m
= [2a + 2(m – 1)d] : [2a’ + 2(m – 1)d’]
= [2a + {(2m – 1) – 1}d] : [2a’ + {(2m – 1) – 1}d’]
= S2m – 1 : S’2m – 1
= [7(2m – 1) + 1] : [4(2m – 1) +27] [using---(1)]
= [14m – 7 +1] : [8m – 4 + 27]
= [14m – 6] : [8m + 23]
Thus the ratio of mth terms of two AP’s is
[14m – 6] : [8m + 23].
I HOPE ITS HELP YOU DEAR,
THANKS
GIVEN RATIO OF SUM OF N TERMS OF TWO AP’s
= (7n+1):(4n+27)--------------(1)
Let’s consider the ratio these two AP’s mth
terms as am : a’m →(2)the nth term of AP
formula, an = a + (n – 1)d
equation (2) ,
am : a’m = a + (m – 1)d : a’ + (m – 1)d’
On multiplying by 2,
we get
am : a’m
= [2a + 2(m – 1)d] : [2a’ + 2(m – 1)d’]
= [2a + {(2m – 1) – 1}d] : [2a’ + {(2m – 1) – 1}d’]
= S2m – 1 : S’2m – 1
= [7(2m – 1) + 1] : [4(2m – 1) +27] [using---(1)]
= [14m – 7 +1] : [8m – 4 + 27]
= [14m – 6] : [8m + 23]
Thus the ratio of mth terms of two AP’s is
[14m – 6] : [8m + 23].
I HOPE ITS HELP YOU DEAR,
THANKS
rohitkumargupta:
thanks for brainliest
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