Question

If three angles (2x+10) and (3x+30)and (5x) are interior for a triangle than value of x?​

Answer 1

according to question

2x+10+3x+30+5x=180°( sum of interior angles of a Triangle)

10x+40=180°

180°-40°=140°

x=140÷10=14°

the angles of the triangle are [2×14+10]+(3×14+30)+5×14

=38°,72°,70°

Answer 2

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If three angles (2x+10) and (3x+30) and (3x+30) are interior for a triangle than value of x ?

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The three angles are-

• (2x+10)
• (3x+30)
• 5x

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The value of x.

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We know that the sum of all angles of a triangle is 180.

So we can say-

$(2x+10)+(3x+10)+5x=180$

⇒ $2x+10+3x+30+5x=180$

⇒ $10x+40=180$

⇒ $10x=180-40$

⇒ $10x=140$

⇒ $x =\frac{140}{10}$

⇒ $x = 14$

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x = 14

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The value of x is 14.

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