Question

If three angles of a triangle are (2x+2) ˚, (3x+3) ˚ and (5x+5) ˚ .find the measure of each angles of a triangle.​

Answer 1

Answer:

36°,54°,90°

Step-by-step explanation:

(2x+2) ˚+(3x+3) ˚+(5x+5) ˚=180°

(angle sum property of triangle)

10x+10=180

10x=170

x=17

the angles are-

(2x+2)°=2(17)+2

=36°

(3x+3)°=3(17)+3

=54°

(5x+5)°=5(17)+5

=90°

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Answer 2

Answer:

Step-by-step explanation:

Step 1: Find the value of x.

We know that, when all the three angles of triangle are added, their sum is 180°.

So,

(2x + 2) + (3x + 3) + (5x + 5) = 180° (Angle sum of a triangle)

2x + 3x + 5x + 2 + 3 + 5 = 180°

10x + 10 = 180°

10x = 180 - 10

10x = 170

x = 170/10

x = 17

Step 2: Substitute the value of x in the angle measures.

Now,

First Angle = 2x + 2 = 2 × 17 + 2 = 34 + 2 = 36°

Second Angle = 3x + 3 = 3 × 17 + 2 = 51 + 3 = 54°

Third Angle = 5x + 5 = 5 × 17 + 5 = 85 + 5 = 90°

Hope this helps!

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