Question

if three angles of a triangle are(x+10)°,2x,(3x-10) then find the value of each of the angle

Answer 1

Answer:

40 , 60 , 80

Step-by-step explanation:

Sum of all angles of a triangle = 180

==: x + 10 + 2x + 3x - 10 = 180

==: 6x = 180

==: x = 30

Angles = x + 10 = 40

           = 2x = 60

           = 3x - 10 = 80

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Answer 2

Step-by-step explanation:

$\bf{\underline{\underline\red{Given:-}}}$

• The three angles if a triangle.

• 1st angle = (x + 10)°

• 2nd angle = 2x°

• 3rd angle = (3x - 10)°

$\bf{\underline{\underline\blue{To\:Find:-}}}$

• The value of each of the angle.

$\bf{\underline{\underline\green{Solution:-}}}$

As we know that:-

In a triangle

The sum of all the three angles = 180°

Given three angles (x+10)° , 2x° , and (3x - 10)°.

So:-

$\rm(x + 10) \degree + 2x \degree + (3x - 10) \degree = 180 \degree$

$\longrightarrow\rm x + 10 + 2x + 3x - 10 = 180 \degree$

$\longrightarrow\rm x + 2x + 3x+ 10 - 10 = 180 \degree$

$\longrightarrow\rm 6x= 180 \degree$

$\longrightarrow\rm x= \dfrac{ 180 }{6}$

$\longrightarrow\rm x= 30 \degree$

Now:-

→ 1st angle = (x + 10)° = 30° + 10° = 40°

→ 2nd angle = 2x = 30° × 2 = 60°

→ 3rd angle = (3x - 10)° = 3(30) - 10 = 90° - 10° = 80°

Therefore:-

The value of each angle of the triangle are 40° , 60° and 80°