Question

If, three angles of a triangle are (x + 10)° + (3x + 5)° + (2x + 15)° , then the value of `x` is​

Answer 1

Step-by-step explanation:

Since, all the angles of a triangle sum to 180∘

∴ ,

5(x−1)+3(2x−5)+9x=180∘

=5x−5+6x−15+9x=180∘

=20x−20=180∘

Taking 20 as common on both the sides and cancelling out each other :-

=20(x−1)=20(9)

=x−1=9

=x=10

So,

∠A=5(10−1) or 45∘

∠B=3(20−5) or 45∘

∠C=90∘

So, it is an Isosceles Right-Angled Triangle

One is shown here in the picture -

Though, it’s a bit small, I’m pretty sure it’s crystal clear.

Hope I answered your Question

Answer 2

Answer:

The value of x = 25°

Step-by-step explanation:

$(x + 10 {}^{o} ) + \: (3x + 5 {}^{o} ) + (2x + 15 {}^{o})$

$sum \: of \: all \:angles \: in \: a \: triangle \: = 180 {}^{o}$

$(x + 10) + (3x + 5) + (2x + 15) = 180$

$x + 3x + 2x + 10 + 5 + 15 = 180$

$6x + 30 = 180$

$6x = 180 - 30$

$6x = 150$

$x = \frac{150}{6}$

$x = 25$

$hence \: the \: value \: of \: x \: = \: 25 {}^{o}$