Question

If three coins are tossed at once, there is a chance of getting at least two prints *

1️⃣ 1/4
2️⃣ 3/8
3️⃣ 1/2
4️⃣ 1/8​

Answer 1

Answer:

getting at least 2 heads

Let E5 = event of getting at least 2 heads. Then,

E5 = {HHT, HTH, THH, HHH}

and, therefore, n(E5) = 4.

Therefore, P(getting at least 2 heads) = P(E5) = n(E5)/n(S) = 4/8 = 1/2

Answer 2

Mark the upper one as Brainliest