if three coins are tossed ,find the probability of ,atleast 1 head ,atmost 1 head ?
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Answered by
2
When we toss three coins simultaneously then the possible of outcomes are: (HHH) or (HHT) or (HTH) or (THH) or (HTT) or (THT) or (TTH) or (TTT)
Total number of outcomes =8
Probability of
atleast 1 head = 7/8
atmost 1 head= 3/8
Total number of outcomes =8
Probability of
atleast 1 head = 7/8
atmost 1 head= 3/8
kushagra52:
is it right
Sorry the second part
Is wrong it will 4/8
how
tmost means 1 or less
At most means it should be 1 to the greatest not more than that
but the probability should be 3/8 (HTT,THT,TTH)
Answered by
1
WHEN THREE COINS ARE TOSSED SIMULTANEOUSLY, THEN ALL POSSIBLE OUTCOMES ARE,
HHH,HHT,HTH,THH,HTT,THT,TTH,TTT
TOTAL NUMBER OF POSSIBLE OUTCOMES = 8.
(1) FAVOURABLE OUTCOMES = 6
P(E) GETTING AT LEAST ONE HEAD = FAVOURABLE OUTCOMES/POSSIBLE OUTCOMES.
= 6/8 = 3/4 ANS
(2) FAVOURABLE OUTCOMES = 4
P(E) GETTING AT MOST 1 HEAD = FAVOURABLE OUTCOMES/ POSSIBLE OUTCOMES = 4/8 = 1/2
HHH,HHT,HTH,THH,HTT,THT,TTH,TTT
TOTAL NUMBER OF POSSIBLE OUTCOMES = 8.
(1) FAVOURABLE OUTCOMES = 6
P(E) GETTING AT LEAST ONE HEAD = FAVOURABLE OUTCOMES/POSSIBLE OUTCOMES.
= 6/8 = 3/4 ANS
(2) FAVOURABLE OUTCOMES = 4
P(E) GETTING AT MOST 1 HEAD = FAVOURABLE OUTCOMES/ POSSIBLE OUTCOMES = 4/8 = 1/2
It is wrong
At least 1 means means 1 or more
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