Question

 If three coins are tossed simultaneously 100 times with the folowing frequecies of different outcomes : Outcome NO head One head Two heads Three heads Frequencey 14 38 36 12 compute the probability of getting atleast one head coming up​

Answer 1

Step-by-step explanation:

Total number of outcomes = 100 

  

Answer 1) : 2 heads coming up 

Probability = 36/100 

= 9/25 

  

Answer 2) : 3 heads coming up  

Probability = 12/100 

= 3/25 

  

Answer 3) : At least 1 head coming up 

Probability = (36/100 + 38/100 + 12/100) 

= 86/100 

= 43/50 

  

Answer 4) : Getting more heads than tails 

Number of times 2 heads (2 heads and 1 tail) appears = 36  

Number of times 3 heads (3 heads and 0 tail) appears = 12 

Number of favorable outcomes = 36 + 12 = 48 

Probability (Getting more heads than tails)  

= Number of favorable outcomes/Total number of possible outcomes 

= 48/100 

= 12/25 

  

Answer 5) : Getting more tails than heads 

Number of times 2 tails (2 tails and 1 head) appears = 38 

Number of times 3 tails (3 tails and 0 head) appears = 14 

Number of favorable outcomes = 38 + 14 =52 

Probability (Getting more tails than heads) = 52/100 

= 13/25