Question

if three coins are tossed simultaneously find the probability of getting attached to head

Answer 1

it's your answer

s={ HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}
n(s) =8

A=getting sample space having attached to head
A={HHH, HHT, HTH, HTT, THH, THT, TTH}
n(A) =7
$p(a) = \frac{n(a)}{n(s)} \\ \\ p(a) = \frac{7}{8}$