Question

If three coins are tossed simultaneously, the find the probability of the following events:
1) Event A - To get tail on the second coin.​

Answer 1

Step-by-step explanation:

When three coins are tossed simultaneously, the total possible outcomes are {(H,H,H) , (H,H,T) , (H,T,H) , (H,T,T), (T,H,H), (T,H,T), (T,T,H), (T,T,T)}.

The total no. of outcomes = 8.

For at most one tail, no. of tails should be either 0 or 1.

The favorable outcomes are

{(H,H,H), (H,H,T), (H,T,H), (T,H,H)}.

No.of favorable outcomes=4.

Therefore, probability of occurrence of atmost 1 tail =4/8 =1/2.

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