If three coins are tossed simultaneously, then the probability of getting at most two heads is
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Possible outcomes -TTT, TTH, THH, HTH, HHT, HTT, HHH, THT
Total possible outcome-8
Favourable outcomes-TTT, THH, THT, HTH, HHT, TTH, HTT
Total favourable outcomes-8
Let the event of getting at most two heads be E.
P(E)=favourable outcomes/Total outcomes
P(E)=7/8
Therefor,the probability of getting almost two heads is 7/8
Total possible outcome-8
Favourable outcomes-TTT, THH, THT, HTH, HHT, TTH, HTT
Total favourable outcomes-8
Let the event of getting at most two heads be E.
P(E)=favourable outcomes/Total outcomes
P(E)=7/8
Therefor,the probability of getting almost two heads is 7/8
rishabhb:
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