if three coins are tossed, what is the probability of getting at least 2heads.
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take all permutations {HHH, HHT,HTH,THH,TTH,THT,HTT,TTT}
Now we have >=2 heads in 1-4 sets
hence the answer is 4/8 = 1/2
Now we have >=2 heads in 1-4 sets
hence the answer is 4/8 = 1/2
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1
4/8=2/4=1/2 P(getting at least two heads)= total number of outcomes/total number of events
Total number of events =8
At least two heads =4/8 =2/4=1/2
Total number of events =8
At least two heads =4/8 =2/4=1/2
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