Physics, asked by YogeshPurbhi, 7 hours ago

If three concurrent forces A, B and C are acting at a point and the angle between
each force is 1200. If force B = 10 N then the value of force A and force Cis
respectively.​

Answers

Answered by pp6672444
4

Answer:

a force = 20 and c Forse = 30

Answered by sourasghotekar123
0

Note: The correct question must be-

If three concurrent forces A, B and C acting at a point and the angle between each force is 120°. If force B=10N, then the value of force A and force C is?

"When three forces acting at a place are in equilibrium, each force is proportional to the sine of the angle between the other two forces," according to Lami's Theorem.

It is written as,

\frac{A}{sin\alpha}=\frac{B}{sin\beta}  =\frac{C}{sin\gamma}

in mathematical or equation form.

Where,

A,Band C are the acting forces while \alpha,\beta and\gamma are the angles made by the forces with each other

Given data,

\alpha=\beta=\gamma=120\circ

B=10N

To find the acting forces A and C,

Using Lami's Theorem,

\frac{A}{sin120\circ}=\frac{B}{sin120\circ} =\frac{C}{sin120\circ}

\frac{A}{\frac{\sqrt{3} }{2} }=\frac{10}{\frac{\sqrt{3} }{2}} =\frac{C}{\frac{\sqrt{3} }{2}  }

\therefore A=C=10N

Hence, the acting forces are 10 Nand 10 N respectively.

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