if three consecutive multiple of 11 is multiplied by 2,3,4 and then added there sum is obtained 814. find the numbers
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Let the three consecutive multiples be 11x, (11x+11) and (11x+22)
The, reqd. equation
=) 2(11x) + 3(11x+11) + 4(11x+22) = 814
=) 22x + 33x + 33 + 44x + 88 = 814
=) 99x = 814 - (33+88)
=) 99x = 814 - 121
=) x = 693/99
=) x = 7
Hence, the multiples are 11x = 77; (11x+11) = 88 and (11x+22) = 99.
HOPE THIS COULD HELP!!!
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