Question

if three consecutive multiple of 11 is multiplied by 2,3,4 and then added there sum is obtained 814. find the numbers

Answer 1

Let the three consecutive multiples be 11x, (11x+11) and (11x+22)

The, reqd. equation

=) 2(11x) + 3(11x+11) + 4(11x+22) = 814

=) 22x + 33x + 33 + 44x + 88 = 814

=) 99x = 814 - (33+88)

=) 99x = 814 - 121

=) x = 693/99

=) x = 7

Hence, the multiples are 11x = 77; (11x+11) = 88 and (11x+22) = 99.

HOPE THIS COULD HELP!!!