Question

If three consecutive multiples of 11 are multiplied by 2 3 and 4 respectively and then added the sum is 814 find each of the multiples ​

Answer 1

Answer:

sorry.................................

Answer 2

Answer:

Let the consecutive numbers be x, 11+x and 22+x

According to question

2x + 3(11+x) + 4(22+x) = 814

2x + 33 + 3x + 88 + 4x = 814

9x + 121 = 814

9x = 814 - 121

x = 693/9

x = 77

Multipiles are

x = 77

11 + x = 88

22 + x = 99

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Step-by-step explanation:

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