Math, asked by vipulvipul6248, 9 months ago

if three cubes whose edges are 6,8,10 respectively are melted and formed into a single cube then the edge and new cube formed is

Answers

Answered by shivamsingh54
4

edge first cube = 6

edge of second cube = 8

edge of third cube =10

Method for finding the answer of this question is--::::::--------------------:::::::::-

the area of first cube is=6×6×6=216

the area of second cube is=8×8×8=512

the area of third cube is=10×10×10=1000

And the volume of the addition of the three cubes is =216+512+1000=1728

For finding the edge of this cube we have to find the cube root of 1728

and the cube root of 1728 because area of cube = side x side × side .

cube root of 1728 equal to 12 because

12×12×12 =1728

I hope it will help you....

if you like this, then please follow me please.........

Answered by ah525407
0

Answer:

the new side of cube after mealting are 18,24,30

Step-by-step explanation:

if three cubes whose edges are 6,8,10 respectively are melted and formed into a single cube then the edge and new cube formed is

we have to find the edges of new cube

before melting cubes are 3

3*6=18

3*8=24

3*10=30

the new side of cube after mealting are 18,24,30

Similar questions