if three cubes whose edges are 6,8,10 respectively are melted and formed into a single cube then the edge and new cube formed is
Answers
edge first cube = 6
edge of second cube = 8
edge of third cube =10
Method for finding the answer of this question is--::::::--------------------:::::::::-
the area of first cube is=6×6×6=216
the area of second cube is=8×8×8=512
the area of third cube is=10×10×10=1000
And the volume of the addition of the three cubes is =216+512+1000=1728
For finding the edge of this cube we have to find the cube root of 1728
and the cube root of 1728 because area of cube = side x side × side .
cube root of 1728 equal to 12 because
12×12×12 =1728
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Answer:
the new side of cube after mealting are 18,24,30
Step-by-step explanation:
if three cubes whose edges are 6,8,10 respectively are melted and formed into a single cube then the edge and new cube formed is
we have to find the edges of new cube
before melting cubes are 3
3*6=18
3*8=24
3*10=30
the new side of cube after mealting are 18,24,30