Question

if three dice are thrown, the probability of showing al different number is ​

Answer 1

Total no. of outcomes = '216'

 

As three dices are thrown simultaneously, all 6 nos. can be shown in 3 dices each.

     

Thus the total no. of outcomes = 6 × 6 × 6 = 6³ = 216.

No. of favourable outcomes = '120'

   

As the favourable outcome meant to show different nos. in each dice, it should be like arranging 6 different nos. in 3 dices each.

Thus no. of favourable outcomes = ⁶P₃ = 6 × 5 × 4 = 120.

     

Thus the probability is,

120/216 = ''5/9''