Question

if three error in the measurement of radius is 2% then the error in tge determination of volume of the sphere
​

Answer 1

Answer:

6%

Explanation:

Percentage error in radius is given as 2% i.e.    

r

Δr

​

×100=2 %

Volume of sphere   V=  

3

4π

​

r  

3

 

Percentage error in volume    

V

ΔV

​

×100=3×  

r

Δr

​

×100=3×2=6 %