Question

IF THREE FORCES 2i^+3j^-k^ and 3i^-18j^-4k^ AND a(i^-3j^-k^) holds a particle in equilibrium. then a is​

Answer 1

hope it's clear........

Answer 2

Answer:

When three forces 2i^+3j^-k^, 3i^-18j^-4k^ and (ai^-3aj^-ak^) acts on particle and particle is in equillibrium then value of a is -5.

Explanation:

Given : Three forces

      F₁= 2i^+3j^-k^

      F₂=3i^-18j^-4k^

      F₃=(ai^-3aj^-ak^)

Now condition given is that these forces hold the particle in equillibrium, which means that the net force acting on particle would be zero.

F$_{net }$ =   F₁+F₂+F₃

        0= (2i^+3j^-k^) + (3i^-18j^-4k^)+(ai^-3aj^-ak^)

        0= (2+3+a)i^+ (3-18-3a)j^+(-1-4-a)k^

        0= (5+a)i^+(-15-3a)j^+(-5-a)k^

0i+0j+0k =(5+a)i^+(-15-3a)j^+(-5-a)k^

on comparing above equation

5+a=0  ,      -15-3a=0  ,   -5-a=0

a= -5

Hence the value of a is -5.