Question

If three forces F1= (i + i +k)N, F2= (i+2j)N and F3=(2i-j + k) N act on a block and
displace it from (2.-3. 4)m to (5, 2, 6)m. The sum of work done by forces on the block is​

Answer 1

Answer:

Three forces F1 = 2 i + j - k N, F2 = 2 i + 3 j - 3 k N, F3 = a( i + j - k) N act simultaneously on a particle. The value of 'a' so that the particle may ...

Explanation:

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