if three lines are drawn on a white board at random with the eyes closed ,show that the probability of forming a triangle is 1/7
Answers
The Required answer is here....
3/21 = 3 ÷ 21
= 1 ÷ 7
3/21 = 1/7
It can be divided further as
3/21 = 1/7
= 1 ÷ 7
3/21 = 0.142......
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Answer:
Step-by-step explanation:
Let AB CD and EF be the three lines.Then there are 7 possible cases.
Case1..... The 3 lines coincide each other
Case2...... The 3 lines pass through a same point ie concurrent lines
Case 3......The 3 lines are parallel to each other.
Case4...... AB and CD are parallel and EF is not
parallel to any of them
Case5.....CD and EF are parallel but AB is not parallel to any of them
Case6..... EF and AB are parallel but CD is not parallel to any of them
Case 7......The 3 lines are not mutually parallel to each other ie form a triangle
Here, no. of favourable outcome=1
No. of possible outcomes=7
:. The required probability is 1/7
Hence shown...
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