If three mangoes cost 60k and two oranges cost 30k What is the total cost of 6 mangoes and 8 oranges
Answers
Answered by
4
Three mangoes 60k.
So each mango = 60/3 = 20k.
Two oranges = 30k.
Therefore each = 30/2 = 15k.
Hence cost of 6 mangoes and 8 oranges = 6 x 20 + 8 x 15 = 120+120 = 240k.
Hope this answer helps you. Please mark as brainliest! :)
So each mango = 60/3 = 20k.
Two oranges = 30k.
Therefore each = 30/2 = 15k.
Hence cost of 6 mangoes and 8 oranges = 6 x 20 + 8 x 15 = 120+120 = 240k.
Hope this answer helps you. Please mark as brainliest! :)
Answered by
1
Answer:
overall it costs 240k
Step-by-step explanation:
mangoes:
3 mangoes---60k
6 mangoes---60×2=120k
oranges:
2 oranges---30k
8 oranges---30×4=120k
overall:
120+120=240k
hope it helps you
Mark as brainliest..
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