Math, asked by elizabethadewuyi9, 9 months ago

If three mangoes cost 60k and two oranges cost 30k What is the total cost of 6 mangoes and 8 oranges

Answers

Answered by theuniverseboss
4
Three mangoes 60k.
So each mango = 60/3 = 20k.
Two oranges = 30k.
Therefore each = 30/2 = 15k.

Hence cost of 6 mangoes and 8 oranges = 6 x 20 + 8 x 15 = 120+120 = 240k.

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Answered by Mahima2007
1

Answer:

overall it costs 240k

Step-by-step explanation:

mangoes:

3 mangoes---60k

6 mangoes---60×2=120k

oranges:

2 oranges---30k

8 oranges---30×4=120k

overall:

120+120=240k

hope it helps you

Mark as brainliest..

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