Math, asked by SinghM6253, 1 year ago

If three metallic spheres of radii 6 cm, 8 cm and 10 cm are melted to form single sphere, the diameter of the sphere is

Answers

Answered by Arcel
9

Answer:

The Diameter of the resulting sphere is 24 cm.

Step-by-step explanation:

Given:

Radius of first sphere (r1) = 6 cm

Radius of second sphere (r2) = 8 cm

Radius of third sphere (r3) = 10 cm

Let us assume the radius of the unknown sphere as = r

From the question we can say that:

\large{\boxed{\boxed{\text{VolumeOfThreeSmallSphere=VolumeOfTheResultingSphere}}}}

Formula to find the volume of Sphere:

\huge{\boxed{\boxed{\red{\sf{4/3\pi r^{3}}}}}}  

Solving the Question:

4/3\pir1^{3}+\pir2^{3}+\pir3^{3}=4/3\pir^{3}

Substituting the values of r in the equation:

4/36^{3}\pi+4/38^{3}\pi+4/310^{3} \pi= 4/3 \pir^{3}

We take 4/3\picommon over here:

4/3\pi(6^{3}+8^{3}+10^{3}) =4/3\pir^{3}

4/3\pi gets canceled:

6^{3} + 8^{3} + 10^{3} = r^{3}

216 + 512 + 1000 = r^{3}

1728 = r^{3}

r^{3} = \sqrt[3]{1728}

r = 12 cm

In the question we are asked to find the Diameter of the Sphere:

Diameter of the sphere = 2 * Radius

=> 2 * 12 = 24 cm

Therefore, the Diameter of the resulting sphere is 24 cm.

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