Question

If three natural numbers a b c are in arithematuc progreession such that a×b×c= 80 the which is the following values can be b

Answer 1

Answer:

b=80/ac

Step-by-step explanation:

Hope it helps........

Answer 2

Answer:

Step-by-step explanation:

Given that ,

three natural number a , b , c are in the arithmetic progression such that a × b × c = 80.

To find the value of b.

So,

a , b , c are in A.P.

Then , (b - a) = ( c - b )          ( 1 )

or    ( b - a ) = 2 ( c - a )         (2)

From (1) we get,

( b - a ) = ( c - b )

b + b = c + a

2b = (c+a)

  b = ( c + a ) / 2

From (2) we get ,

( b - a ) = 2 ( c - a )

b - a = 2c - 2a

  b = 2c - 2a + a

  b = ( 2c -a )

And from the given question ,

a × b × c = 80.

 b = 80/ac

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