Question

If three number are chosen at random from 0 to 25 find the probability that they are consecutive?

Answer 1

no. of ways in which 3 numbers can be chosen out of 26 =26C3
no. of ways in which the numbets can be consecutive =25
({0,1,2},{1,2,3},{2,3,4}......and so on)
thus requried probability is:-

25/26C3
=(25×6)/(26×25×24)
=6/(26×24)
=1/104