If three numbers are chosen from 1 to 30 randomly, the probability that they are consecutive
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probablity= no. of favourable events/total no. of events
no. of favourable events:
pairs- (1,2,3)(2,3,4)......(28,29,30). so there are obviously 28 terms
total:
28*29*30/1*2*3 = 243600/6 = 4060
So, probablity= 28/4060= 1/145
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Answer:
....................................3/30
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